A rectangular park is 80 m long and 60 m wide. Two crossroads, each of width 10 m, cut at right
angles through the centre of the rectangular park. Find the area of the paths. Also, find the area
of the park that is not covered by the paths.
Answers
Answer:
Here, PQ=10m and PS=300m, EH=10m and EF=700m
And KL=10m and KN=10m
Area of roads = Area of PQRS+Area of EFGH−Area of KLMN
[∵ KLMN is taken twice, which is to be subtracted]
=PS×PQ+EF×EH−KL×KN
=(300×10)+(700×10)−(10×10)
=3000+7000−100
=9,900m
2
Area of road in hectares, 1m
2
=
10000
1
hectares
∴9,900m
2
=
10000
9900
=0.99 hectares
Now, Area of park excluding cross roads = Area of park−Area of road
=(AB×AD)−9,900
=(700×300)−9,900
=2,10,000−9,900
=2,00,100 m
2
=
10000
200100
hectares=20.01 hectares.
Step-by-step explanation:
hope it helps you bro have a great day
Answer:
Here, PQ 10m and PS= 300m, EH= 10m and EF=700m
And KL 10m and KN= 10m
Area of roads = Area of PQRS+Area of EFGH Area of KLMN
[. KLMN is taken twice, which is to be
subtracted]
= PS X PQ+EF - EH - KL × KN
= (300x10) + (700 × 10) - (10 × 10)
= 3000 + 7000 - 100
= 9, 900m²
Feedback
Σ
1 Area of road in hectares, 1m² = hectares 10000 = 0.99 hectares ... 9, 900m² : 9900 10000
Now, Area of park excluding cross roads =
Area of park-Area of road = (ABX AD) - 9, 900
= (700 × 300) - 9,900
= 2, 10, 000 - 9,900
= 2, 00, 100 m²
200100
10000
hectares 20.01 hectares.