Math, asked by aairahahmed99, 16 days ago

A rectangular park is 80 m long and 60 m wide. Two crossroads, each of width 10 m, cut at right
angles through the centre of the rectangular park. Find the area of the paths. Also, find the area
of the park that is not covered by the paths.​

Answers

Answered by gamingwithpiyush047
0

Answer:

Here, PQ=10m and PS=300m, EH=10m and EF=700m

And KL=10m and KN=10m

Area of roads = Area of PQRS+Area of EFGH−Area of KLMN

[∵ KLMN is taken twice, which is to be subtracted]

=PS×PQ+EF×EH−KL×KN

=(300×10)+(700×10)−(10×10)

=3000+7000−100

=9,900m

2

Area of road in hectares, 1m

2

=

10000

1

hectares

∴9,900m

2

=

10000

9900

=0.99 hectares

Now, Area of park excluding cross roads = Area of park−Area of road

=(AB×AD)−9,900

=(700×300)−9,900

=2,10,000−9,900

=2,00,100 m

2

=

10000

200100

hectares=20.01 hectares.

Step-by-step explanation:

hope it helps you bro have a great day

Answered by supriyalalit20
0

Answer:

Here, PQ 10m and PS= 300m, EH= 10m and EF=700m

And KL 10m and KN= 10m

Area of roads = Area of PQRS+Area of EFGH Area of KLMN

[. KLMN is taken twice, which is to be

subtracted]

= PS X PQ+EF - EH - KL × KN

= (300x10) + (700 × 10) - (10 × 10)

= 3000 + 7000 - 100

= 9, 900m²

Feedback

Σ

1 Area of road in hectares, 1m² = hectares 10000 = 0.99 hectares ... 9, 900m² : 9900 10000

Now, Area of park excluding cross roads =

Area of park-Area of road = (ABX AD) - 9, 900

= (700 × 300) - 9,900

= 2, 10, 000 - 9,900

= 2, 00, 100 m²

200100

10000

hectares 20.01 hectares.

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