A rectangular park is 800m long and 400m wide. Two cross road each of width 10m wide cut at right angles through the center of the park and parallel to its sides. Find the total area of the park without the roads.
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8
area of park excluding area of roads = Area of park - area of roads
area of park= l×b = 800×400 = 320000m²
area of 1st road= 800×10 = 8000m²
area of 2nd road = 400×10 = 4000m²
but it will make a rectangular box in centre of both roads that's why
area of rectangular box = 10×10 = 100m²
therefore , Area of both roads = 4000+8000-100 = 11900m²
area of pard excluding the roads = 320000-11900
= 308100m²
Answered by
0
Step-by-step explanation:
area of park excluding area of roads = area of park - area of roads
area of park= l×b=800×400=320000msq.
area of first road=800×10=8000m
area of second road=400×10=400m
therefore,area of both roads=4000+8000-100
= 11900m sq.
area of park excluding the roads=
3,20,000-11,900
=3,08,100 sq.m
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