a rectangular Park is of length 45 metre and breadth 30 metre to cross paths parallel to the side of the park and passing through the centre at right angle let down in it what is the total area of the path if the width of path is 5m
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Area of rectangle ABCD=AB×BC
=(45×30)m^2
=1350m^2
Area of rectangle efgh=ef×4fg
=(45×5)=225m^2
Area of rectangleKlmn =kl×lm
=kl×lm=5×30=150m^2
Area of square qrst= qr×qr
=5×5=25m^2
Area of path=area of rectangle ABCD-(Area of rectangle efgh+area of rectangle klmn-Area of square qrst)
=1350-(225+150-25)
=1350-(375-25)
=(1350-350)m^2
=1000m^2
than
Area of path=1000m^2
=(45×30)m^2
=1350m^2
Area of rectangle efgh=ef×4fg
=(45×5)=225m^2
Area of rectangleKlmn =kl×lm
=kl×lm=5×30=150m^2
Area of square qrst= qr×qr
=5×5=25m^2
Area of path=area of rectangle ABCD-(Area of rectangle efgh+area of rectangle klmn-Area of square qrst)
=1350-(225+150-25)
=1350-(375-25)
=(1350-350)m^2
=1000m^2
than
Area of path=1000m^2
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