Question

A rectangular park is to be designed whose breadth is 3 less than its length. It's area is to be 4 square meters more than the area of a park that has already has been made in the shape of an isosceles triangle with it's base as the beadth of the rectangular park and of altitude 12m. Find it's length and breadth​

Answer 1

Answer:

it's ur answer

hope it helps

Answer 2

Answer:

Here is your answer

Step-by-step explanation:

Let the the rectangular park be< x >metre.

So, it's length =x+3 metre

therefore the area of the rectangular Park is =x(x+3)m^2.

=

${x}^{2} + 3x \: {m}^{2}$

therefore its area is equal to

$\frac{1}{2} \times x \times 12 = 6x \: {m}^{2}$

Therefore

${x}^{2} + 3x = 6x + 4 \\ {x}^{2} - 3x - 4 = 0$

By using quadratic formula

x=4,-1

Side can't be negative

Breadth=4m

Length will be 7m

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