Math, asked by sanskritikakran, 3 months ago

a rectangular park of dimensions 40m×30m and a sqaure park side 120 m have to be developed at the cost of rs 560m2 find the total cost involved in developing the parks​

Answers

Answered by Silentheart0
8

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Given, dimensions of rectangular park 50mx40m =

So, Are of park = 50*40 = 2000sq.m

Area of the grass strip surrounding the pond = 1184 sq.m

Hence, area of the pond = 1b = 2000-1184

= 816sq.m

→ Lb = 816sq.m

Let the width of the grass strip be 'x'

So, (50-2x)(40-2x) = 816

2000 - 100x - 80x + 4x2 = 816

- 2000-180x+4x2 = 816

→ 4x2-180x+1184 = 0

→x2-45x+296 = 0

→x2-37x-8x+296=0

→x=37, x=8

But x=37 is not possible

.. Width of the grass strip = 8m

Length of the pond = 50-16 = 34m

Breadth of the pond = 40-16 = 24m

Answered by tellmetheans
3

Answer:

8736000 rs

Step-by-step explanation:

area of rec park =40*30

= 1200m^2

ar( square) =a^2

= 120*120

=14400m^2

total area = 15600m^2

cost =15600* 560

= 8736000

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