A rectangular park of perimeter 320 & area 4800 if so find it's length & breadth
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Answer:
Length = 120 units
Breadth = 40 units
Step-by-step explanation:
let the length = x
and breadth = y
Area of park= length × breadth
=>4800 = xy ---> (i)
Perimeter of park = 2(x + y)
=>320 = 2x + 2y
=>160 = x + y
=>y = 160 - x ----> (ii)
From eqn (i) :
=>xy = 4800
=> x(160-x) = 4800 {from eqn (ii) }
=> 160x - x² = 4800
=> x² - 160x + 4800 = 0
=> x= 160±√(-160)² - 4(4800)/2
=> x= 160±√25600 - 19200/2
=> x= 160±√6400/2
=> x= 160±80/2
=> x= 160 + 80/2 ; 160 - 80/2
=> x= 240/2 ; 80/2
=> x= 120 ; 40
Now taking x= 40 ,we get:
=>y = 160 - x
=>y = 160 - 40
=>y = 120 {Since, breadth is greater than length, So we take x = 120}
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