A rectangular park whose length is 30 m and breath is 20 m is to be fenced with a barded wire. How much of barded wire is needed?
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the wire needed is to be of length of perimeter of park
park is rectangular
so it's perimeter is = 2 ( l + b )
= 2 ( 30 + 20 )
= 2 × 50
= 100 meter
park is rectangular
so it's perimeter is = 2 ( l + b )
= 2 ( 30 + 20 )
= 2 × 50
= 100 meter
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