A rectangular piece of ground is 60 m long and 45 m wide. Find the cost of levelling it at
80 paise per square metre.
Answers
Step-by-step explanation:
Solution :-
Length = 45 m
Breadth = 30 m
Area of whole piece of rectangular land = L*B
⇒ 45*30 = 1350 m²
So, area of the whole rectangular piece of land = 1350 m²
Now,
Length of the 1st road parallel to the length = 45 m
Breadth of the 1st road parallel to the length = 1 m
Area of the 1st road = 45*1
= 45 m²
Length of the 2nd road parallel to the breadth = 30 m
Breadth of the 2nd road parallel to the breadth = 1 m
Area of the 2nd road = 30*1
= 30 m²
Area of the common part of 2 roads = 1*1
= 1 m²
Total area of 2 roads = Area of 1st road + Area of 2nd road - Area of common part
⇒ (45 + 30) - 1
⇒ 75 - 1
= 74 m²
So, the area of the 2 roads is 74 m²
Now,
Area of the remaining ground = Area of the whole rectangular piece of land - Area of 2 roads
⇒ 1350 - 74
= 1276 m²
Area of the remaining ground is 1276 m².
Answer:
₹2160
Step-by-step explanation:
L=60m
B=45
Now,
area of rectangle =L×B
=60×45
=2700m^2
Now,.
cost of levelling it =80 paise per square metre
therefore
cost of leveling =2700×80
=216000 paise
Converting in rupees = 216000/100
=₹2160.00