A rectangular piece of iron sheet is 44 m long and 20 m broad. It is rolled along its length to form a cylinder. Find the volume of the cylinder so formed.
Answers
Answered by
31
Length of the paper = 44 m
breadth = 20m
now it is rolled along its length
so the circumference = 44m
and height of the cylinder will be 20 m
we have to find r
2πr = 44
r = 44/2 × 7/22
r = 7 m
volume of cylinder = πr²h
= 22/7 × 7 × 7 × 20
= 3080 m³
breadth = 20m
now it is rolled along its length
so the circumference = 44m
and height of the cylinder will be 20 m
we have to find r
2πr = 44
r = 44/2 × 7/22
r = 7 m
volume of cylinder = πr²h
= 22/7 × 7 × 7 × 20
= 3080 m³
Answered by
16
Length = 44m
Breadth = 20m
Circumference = 44m
2*22/7*r = 44
44/7 *r = 44
44r = 7*44
r = 7*44/44
r = 7
22/7*7*7*20 = 3080
Breadth = 20m
Circumference = 44m
2*22/7*r = 44
44/7 *r = 44
44r = 7*44
r = 7*44/44
r = 7
22/7*7*7*20 = 3080
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