Question

A rectangular piece of paper 11 cm × 4 cm is folded without overlapping to make a cylinder of height 4 cm. Find the volume of the cylinder.

Answer 1

Solution:

Length of the paper will be the perimeter of the base of the cylinder and width will be its height.

Circumference of base of cylinder = 2πr = 11 cm

2 x 22/7 x r = 11 cm

r = 7/4 cm

Volume of cylinder = πr2h = (22/7) x (7/4)2 x 4

= 38.5 cm3

Answer 2

Answer : )

Given a Rectangular piece of paper 11cm×4cm is folded without overlapping to make a cylinder of height 4 cm

The length of the paper becomes the circumference of the base of the cylinder and width becomes height.

Let radius of the cylinder=r and height=h

Circumference of the base of cylinder =2πr=11cm

⇒2×22/7×r=11

∴r=7/4cm

 Now h=4cm

Volume of the cylinder (V)=πr²h

=22/7×7/4×7/4×4cm³

=38.5cm3

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