A rectangular piece of paper 11 cm × 8 cm is folded without overlapping to make a cylinder of height 8 cm. Find the volume of the cylinder.
Answers
Given a Rectangular piece of paper 11cm×4cm is folded without overlapping to make a cylinder of height 4 cm
The length of the paper becomes the circumference of the base of the cylinder and width becomes height.
Let radius of the cylinder=r and height=h
Circumference of the base of cylinder =2πr=11cm
⇒2×
7
22
×r=11
∴r=
4
7
cm
Now h=4cm
Volume of the cylinder (V)=πr
2
h
=
7
22
×
4
7
×
4
7
×4cm
3
=38.5cm
3
Answer :
- Volume of cylinder = 77cm³
Given :
- A rectangular piece of paper 11cm × 8cm is folded without overlapping to make a cylinder of height 8cm
To find :
- Volume of cylinder
Solution :
Given,
- Length of rectangle = 11cm
- Breadth of rectangle = 8cm
Here, A rectangular piece of paper is folded without overlapping to make a cylinder so,
- Height of cylinder = breadth of rectangle (8cm)
- Let the radius of rectangle be r
A rectangular piece of paper is folded without overlapping to make a cylinder so,
- Perimeter of rectangle (bottom) = Length of the rectangle
Here,
- Circumference of circle is 11cm
- Height is 8cm
As we know that
- Circumference of circle = 2πr
We need to find the radius of cylinder
⇢ 2πr = 11
⇢ 2 × 22/7 × r = 11
⇢ 44/7 × r = 11
⇢ r = 11 × 7/44
⇢ r = 7/4
Hence , Radius is 7/4
Now, we need to find the volume of cylinder
As we know that,
- Volume of cylinder = πr²h
⇢ Volume of cylinder = πr²h
⇢ Volume of cylinder = 22/7 × (7/4)² × 8
⇢ Volume of cylinder = 22/7 × 7/4 × 7/4 × 8
⇢ Volume of cylinder = 77cm³
Hence , Volume of cylinder = 77cm³