Question

A rectangular piece of paper 11 cm x 4 cm is rolled to make a right circular cylinder of height 4 cm.

Find the volume of the cylinder.?​

Answer 1

Answer:

44cm²

Explanation:

Given dimensions of the rectangular piece of paper is 11cm × 4cm.

Rolling in right circular cylinder the length becomes the circumference and the breadth become the height of the base.

To find the volume of the cylinder we require the radius of the base.

We know that,

Circumference of the base of a cylinder :

$\sf = 2\pi \boldsymbol{r}$

Where,

• circumference is 11cm.
• ‘r’ denotes radius of the base.
• $\sf Taking \: \pi \: as \: \dfrac{22}{7}$

$\sf \therefore \: 11 = 2 \times \dfrac{22}{7} \boldsymbol r$

Finding ‘r’ :-

$\sf \implies \: 11 = 2 \times \dfrac{22}{7} \times \boldsymbol r$

$\sf \implies \: 11 = \dfrac{44}{7}\boldsymbol r$

$\sf \implies \: \dfrac{11 \times 7}{44} =\boldsymbol r$

$\sf \implies \: \frac{7}{4} = \boldsymbol r$

${ \underline{\sf \: \therefore The \: radius \: is \: \dfrac{7}{4}cm }}$

Now,

Volume of a cylinder = $\sf 2\pi \boldsymbol{rh}$

Where,

• $\boldsymbol{r} = {\sf{\dfrac{7}{4}cm}}$
• $\boldsymbol{h} = {\sf{ 4cm}}$
• Taking $\sf \pi \: as \: \dfrac{22}{7}$

$\sf \therefore \: volume = 2 \times \dfrac{22}{7} \times \dfrac{7}{4} \times 4$

$\sf \: = 44 {cm}^{2}$

∴ Volume of the cylinder is 44cm²

Answer 2

Answer:

No I am having fun but a bit crazy with my big bro

Because he just done something g with my I Mac and now he is repairing it