Question

a rectangular piece of paper 11 x 4cm is folded without overlapping to make a cylinder of height 4 cm.find the volume of cylinder

Answer 1

length of rectangular paper = perimeter if base of cylinder
width of rectangular paper = height of cylinder
let the radius of base if cylinder be r
perimeter of base if cylinder= 2πr
therefore 2πr=11cm
or 2×22/7× r= 11
therefore r= (11×7)/(2×22)=7/4
volume of cylinder=πr^2h
=22/7×7/4×7/4×4
=38.5
hope this help

Answer 2

Answer:

$\small{\boxed{\bold{The\:volume\:of \:cylinder\:is\:38.5cm^3}}}$

$\tt{Given}\begin{cases}\tt{11cm} \\ \tt{4cm} \\\tt{4cm}\end{cases}$

$\large\underline\textsf{To find }$

$\small\textsf{the volume of the cylinder }$

$\large\underline\textsf{Suppose:- }$

$\large\bf{ Radius \:of \:cylinder =\red R}$

$\large\bf{And \:Hieght =\red H}$

$\huge\underline\textsf{Explantion:- }$

$\implies\sf perimeter \: of \: the \: base \: of \: the \: cylinder = 2\pi \: r = 11$

$\implies\sf2 \times \frac{22}{7} \times r = 11$

$\implies\sf r = \frac{7}{4} cm$

$\implies\sf volume \: of \: cylinder = v = \pi \: r {}^{2} h$

$\implies\sf \frac{22}{7} \times \frac{7}{4} \times \frac{7}{4} \times 4cm {}^{3}$

$\leadsto\bf38.5cm {}^{3}$