Question

a rectangular piece of paper 11cm*4cm is folded without overlapping to make a cylinder of height 4cm . find the surface area of the closed cylinder.
Class 10 please help fast we ith correct answer
AND I WANT AREA OF CLOSED SURFACE AREA. '' I DON'T WANT THE VOLUME PLEASE''​

Answer 1

Answer:

38.5 cm^3

Step-by-step explanation:

Given that,

Length of the rectangular paper= 11cm

Breadth of the rectangular paper= 4cm

Circumfernce of circular part of cyclinder = 2∏r

also given that cyclinder is rolled along its length

Hence Circumfernce of circular part of cyclinder =Length of the rectangular paper

2∏r =11cm

2 X 22 / 7 X r = 11

44 / 7 X r = 11

r = 7 / 4 cm

Height of cylinder =Breadth of the rectangular paper = h =4cm

Volume of cyclinder =∏r2h

=22 / 7 x (7/4)2X 4

= 38.5cm^3

PLEASE MARK THIS ANSWER AS BRAINLIEST.......

Answer 2

Answer:

38.5 cm^3...............