Question

A rectangular piece of paper 11cm multiply 4cm is folded without overlapping to make a cylinder of heights 4cm . find the volume of the cylinder. ​

Answer 1

Answer:

$\small{\boxed{\bold{ The\:volume\:of \:cylinder\:is\:38.5cm^3}}}$

$\tt{Given}\begin{cases}\tt{11cm} \\ \tt{4cm} \\\tt{4cm}\end{cases}$

$\large\underline\textsf{To find }$

$\small\textsf{the volume of the cylinder }$

$\large\underline\textsf{Suppose:- }$

$\large\bf{ Radius \:of \:cylinder =\red R}$

$\large\bf{And \:Hieght =\red H}$

$\huge\underline\textsf{Explantion:- }$

$\implies\sf perimeter \: of \: the \: base \: of \: the \: cylinder = 2\pi \: r = 11$

$\implies\sf2 \times \frac{22}{7} \times r = 11$

$\implies\sf r = \frac{7}{4} cm$

$\implies\sf volume \: of \: cylinder = v = \pi \: r {}^{2} h$

$\implies\sf \frac{22}{7} \times \frac{7}{4} \times \frac{7}{4} \times 4cm {}^{3}$

$\leadsto\bf38.5cm {}^{3}$

Answer 2

CIRCUMFERENCE OF CYLINDER =2πr

=2×22/7×r×11

=44/7×r×11

=r=7/4

=VOLUME OF CYLINDER=2π²r

=22/7×(7/4)²×4cm

=22/7×(7/4)×(7/4)×4cm

=22×7/4

=154/4

=77/4

=38.5cm³

OKAY