Question

A rectangular piece of paper 11cm x 4 cm is folded
without overlapping to make a cylinder of height
4cm. Find the surface area of the cylinder.
I need full steps
those who dont know plss dont answer it
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Answer 1

Given that,

Length of the rectangular paper= 11cm

Breadth of the rectangular paper= 4cm

Circumfernce of circular part of cyclinder = 2∏r

also given that cyclinder is rolled along its length

HenceCircumfernce of circular part of cyclinder =Length of the rectangular paper

2∏r =11cm

2 X 22 / 7 X r = 11

44 / 7 X r = 11

r = 7 / 4 cm

curved surface area =

2pi r ×h

2×22/7×7/4× 11

= 121 cm sq.

hope itz gonna help....