A rectangular piece of paper 22 cm long and 12 cm broad is rolled along its length
to form a cylinder. Find the total surface area of the cylinder so formed, supposed
the top and bottom is closed.
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Answer:
1056 sq cm
Step-by-step explanation:
Given l= 22 cm, b= 12cm
To find
Total surface area of cylinder= 2× pi× r (h+r)
where h=l and r= b/2
therefore h=22cm,r= 6 cm
Now, Total surface area of cylinder= 2×22/7×6(22+6)
2×22/7×6×28
= 2×22×6×4
=1056 sq cm
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