Question

A rectangular piece of paper 44 cm 28 cm is folded without overlapping to make a cylinder
of height 28 cm. Find the volume of the cylinder.

Answer 1

Answer:

4312 cm³

Step-by-step explanation:

Given that a rectangular paper is folded to make a cylinder,

=> the length of the rectangle = circumfrence of the base of the cylinder

ie., 2$\pi$r = 44cm  

=> r = 44*$\frac{7}{22}$*$\frac{1}{2}$ cm

=> r = 7cm

also, it implies that the breadth of the rectangle = height of the cylinder

=> h, height of the cylinder = 28cm

so, the volume of the cylinder = $\pi$r²h cu.units

                                                  = $\frac{22}{7}$*7*7*28 cm³

                                                   = 22*7*28 cm³

                                                   = 4312 cm³

                       

Answer 2

Given : A rectangular piece of paper 44 cm × 28 cm is folded without overlapping to make a cylinder of height 28 cm.

To find : The volume of the cylinder.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the volume of the cylinder)

In case of the given rectangular paper :

• Length = 44 cm
• Breadth = 28 cm

If we form such a cylinder, then -

• Height of the cylinder = Breadth of the rectangular paper = 28 cm (given)
• So, Circumference of the base of the cylinder = Length of the rectangular paper = 44 cm

Let, the radius of the base of the cylinder = r cm

Circumference of the base :

= 2 × π × radius

= 2 × (22/7) × r

= (44r/7) cm

Comparing the two values of the circumference of the base of the cylinder :

44r/7 = 44

r = 44 × 7/44

r = 7

So, the radius of the base of the cylinder = r cm = 7 cm

So, the volume of the cylinder will be :

= π × (radius)² × height

= (22/7) × (7)² × 28

= 4312 cm³

(This will be considered as the final result.)

Hence, the volume of the cylinder will be 4312 cm³