A rectangular piece of paper is 22 cm in length and 10 cm in width . it is rolled into a cylinder along its length . find the surface area of this cylinder
Answers
Answered by
2
Answer:
Step-by-step explanation:
Circumference of circle = l of rectangle
R=c/2(π)
=22*7/44=7/2
Total area=22/7*72*10+2*22/7*7/2
Area=132cm^2
Answered by
1
Length of paper =Circumference of circle = 22cm
Width of paper = height of cylinder =10cm
Then,
Circumference = 22cm
2 x (22/7) x r =22
r =7/2 = 3.5 cm
Now,
Curved surface area of cylinder = 2 x 22/7 x r x h
= 2 x 22/7 x 3.5 x 10
=220 cm^
Total surface area = 220+2 x (22/7) x 3.5^
=220 + 77
=297 cm^
Width of paper = height of cylinder =10cm
Then,
Circumference = 22cm
2 x (22/7) x r =22
r =7/2 = 3.5 cm
Now,
Curved surface area of cylinder = 2 x 22/7 x r x h
= 2 x 22/7 x 3.5 x 10
=220 cm^
Total surface area = 220+2 x (22/7) x 3.5^
=220 + 77
=297 cm^
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