A rectangular piece of paper is 22 cm in length and 10 cm in width.I t is rolled into a cylinder along its length.Find the surface area of this cylinder.
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hey... frnd...
here's ur answer!
area of the rectangular paper=CSA of the cylinder
area of the rectangle=l×b
=22×10
=220cm²
therefore the CSA of the cylinder is also 220cm²
height of the cylinder=breadth of rectangle
therefore height of cylinder=10cm
CSA of the cylinder=220cm²
2πrh=220cm²
2×22/7×r×10=220cm²
440/7×r=220cm²
r=220/1×7/440
r=7/2cm
surface area(TSA) of the cylinder=2πr(h+r)
=2×22/7×7/2(20+7/2)
=22(40+7/2)
=11×47
=517cm²
hope this helps...
here's ur answer!
area of the rectangular paper=CSA of the cylinder
area of the rectangle=l×b
=22×10
=220cm²
therefore the CSA of the cylinder is also 220cm²
height of the cylinder=breadth of rectangle
therefore height of cylinder=10cm
CSA of the cylinder=220cm²
2πrh=220cm²
2×22/7×r×10=220cm²
440/7×r=220cm²
r=220/1×7/440
r=7/2cm
surface area(TSA) of the cylinder=2πr(h+r)
=2×22/7×7/2(20+7/2)
=22(40+7/2)
=11×47
=517cm²
hope this helps...
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