A rectangular piece of paper is 22 cm in length and 10 cm in width. It is rolled into a cylinder along its length. Find the surface area of this cylinder.
Answers
Answered by
170
Hey mate here your answer
cicumference of the of the box of a cylinder =
lenght of a rectangle=2/πr
r=22cm
h=10cm
csa= 2/πrh = 22×10
220cm^2
cicumference of the of the box of a cylinder =
lenght of a rectangle=2/πr
r=22cm
h=10cm
csa= 2/πrh = 22×10
220cm^2
Answered by
327
Solutions
length of paper = Circumference = 22 cm
Width of paper = height of cylinder = 10 cm
Then,
Circumference of circle = 22 cm
=> 2πr = 22
=> 2x(22/7) x r = 22
=> r = 7/2 = 3.5 cm
Now,
Curved Surface Area of cylinder = 2πrh
= 2 x (22/7) x 3.5 x 10
= 220 cm²
Thanks
length of paper = Circumference = 22 cm
Width of paper = height of cylinder = 10 cm
Then,
Circumference of circle = 22 cm
=> 2πr = 22
=> 2x(22/7) x r = 22
=> r = 7/2 = 3.5 cm
Now,
Curved Surface Area of cylinder = 2πrh
= 2 x (22/7) x 3.5 x 10
= 220 cm²
Thanks
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