A rectangular piece of paper is 22 cm in length and 10 cm in width.It is rolled into a cyclinder along its length. find the surface area of this cyclinder
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length of paper=height of cylinder
ie,h=22cm
diameter=10cm(breadth) radius =5cm
surface area of cylinder=2πrh
ie,2x22/7x5x22=691.42cm^2
ie,h=22cm
diameter=10cm(breadth) radius =5cm
surface area of cylinder=2πrh
ie,2x22/7x5x22=691.42cm^2
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