A rectangular piece of paper is 22 cm in length and 10cm in width.it is rolled into a cylinder along it's length . Find the surface area of this cylinder.
Mrittika050902:
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Answered by
3
hey friend here is your answer
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A rectangular piece of paper is 22 cm in length and 10cm in width.it is rolled into a cylinder along it's length .
so,the area of the paper is the surface area of this cylinder.
so the surface area of cylinder is = 22×10 cm^2
=220 cm square
_______________________________
hope it helps you
Mark as brainliest☺️☺️✌️✌️❤️❤️
_______________________________
A rectangular piece of paper is 22 cm in length and 10cm in width.it is rolled into a cylinder along it's length .
so,the area of the paper is the surface area of this cylinder.
so the surface area of cylinder is = 22×10 cm^2
=220 cm square
_______________________________
hope it helps you
Mark as brainliest☺️☺️✌️✌️❤️❤️
Answered by
5
if any rectangular paper sheet rolled along to it's length then in this case we got a cylinder and height of this particular cylinder will be equal to the breadth of the paper sheet and also circumference of the base of this cylinder will be equal to the length,
then
h=breadth=10 cm,
also,
2πr=22 cm,
2×22/7×r=22 cm,
then
r=7/2 cm,
then
C.S.A of the cylinder =2πrh
=2×22/7×7/2×10,
=220 cm²
then
h=breadth=10 cm,
also,
2πr=22 cm,
2×22/7×r=22 cm,
then
r=7/2 cm,
then
C.S.A of the cylinder =2πrh
=2×22/7×7/2×10,
=220 cm²
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