Question

A rectangular piece of paper llcm x 4 cm is folded without overlapping to make a
cylinder of height 4 cm. Find the curved surface area of cylinder.​

Answer 1

Answer:

44 is the curved surface area

Step-by-step explanation:

length of rectangle = circumference of circle

11cm is the circumference

2πr=11

2*22/7r=11

r=11*7/2*22

r=7/4

C.S.A of cylinder=2πrh

2*22/7*7/4*4=44cm^2

Answer 2

CSA of the Cylinder is 44 cm²

Step-by-step explanation:

We Have :-

A rectangle :-

Length = 4 cm

Breadth = 11 cm

Cylinder :-

Height = 4 cm

Circumference = 11 cm

To Find :-

CSA of the Cylinder

Formula Used :-

$perimeter \: of \: the \: circle \: = \: 2 \: \pi \: r \\ \\ csa \: of \: the \: cylinder \: = \: 2 \: \pi \: r \: h$

Solution :-

$perimeter \: of \: the \: circle \: = \: 2 \: \pi \: r \\ \\ perimeter \: = \: 11 \: cm \\ \\ csa \: of \: the \: cylinder \: = \: 2 \: \pi \: r \: h \\ \\ csa \: = 11 \times 4 \\ \\ csa \: = \: 44 \: {cm}^{2}$

CSA of the Cylinder is 44 cm²