Question

A rectangular piece of paper of width 20 cm and
length 44cm is rolled along its width
to form a cylinder
what is the C.S.A. Of the cylinders
please answer fast​

Answer 1

Given

A rectangular piece of paper of width 20 cm and length 44cm is rolled along its width to form a cylinder.

Find out

Curved surface area of the cylinder

Solution

When rectangular piece of paper rolled along its width to form cylinder then,

➡ Length of rectangle = circumference of base of cylinder = 44cm

➡ Breadth of rectangle = height of cylinder = 20 cm

Now, curved surface area of cylinder

➡ 2πrh

➡ circumference of base × height

➡ 44 × 20

➡ 880cm²

Additional Information

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Volume of cube = a³
• Volume of sphere = 4/3πr³
• Surface area of sphere = 4πr²
• Volume of hemisphere = ⅔ πr³
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

$\rule{200}3$

Answer 2

Given:

• Length of rectangular paper = 44cm
• Breadth = 20cm
• It is rolled in the form of cylinder

To find:

• C.S.A of cylinder

Solution:

We know that

C.S.A = 2πrh = circumference of base × height

Because , 2πr = Circumference of circle & h = height.

Labelling the formula

• C.S.A : Curved surface area
• r : radius of cylinder
• h : height of cylinder

Here , circumference of base = length of rectangular paper & Height = breadth of rectangular paper . Since , the rectangular paper is rolled

→ 44 × 20

→ 880 cm². [ answer]