A rectangular pit of dimensions 30m×15m×12m is dug and the earth taken out is disposed off in a carrier which can carry a maximum load of 540m3 of earth. The least number of rounds the carrier had to make to dispose off the earth dug out is *
Answers
Answer:
The Carrier had to make at least 10 rounds.
Step-by-step explanation:
In context to the given question;
we have to find the least number of rounds the carrier had to make to dispose off the earth dug out.
Given;
Dimensions of rectangular ( cuboidal) = 30m x 15m x 12m
Maximum load in one round of a carrier = 540m³
Volume of the dig = 30m x 15m x 12m
= 5,400 m³
Number of rounds the carrier had to make
= volume of the dig / max. load in one round
= 5,400 / 540
= 10 rounds
Therefore, The Carrier had to make at least 10 rounds
Answer:
The carrier have to make at least 10 rounds to dispose off the earth dug.
Step-by-step explanation:
Given: The dimensions of the pit = 30m×15m×12m
We know that volume = Length * Breadth * Height
Therefore, the volume of the earth dug out = 30m * 15m * 12m
= 5400m³
It is also given that a carrier can carry a maximum load of 540m³
We need to find the minimum number of rounds the carrier has to make to dispose off the earth dug.
We know that
Total amount of earth dug = Amount in 1 round * No. of rounds
On substituting the values, we get,
5400m³ = 540m³ * No. of rounds
=> No. of rounds = 5400m³/540m³
= 10
Therefore, the carrier have to make at least 10 rounds to dispose off the earth dug.