A rectangular plate 0.6 m wide and 1.2 m deep is submerged in an oil bath of specific gravity 0.8.
The maximum and minimum depths of the plate are 1.6 m and 0.75 m from the free
surface. Calculate the hydrostatic force on one face of the plate, and the depth of centre of
pressure.
2+2+6
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tell me the right answer because to be because 2 + 2 + 6 answer 10
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Answer:
Force= 3.81 KN
Height= 36 m
Explanation:
Given, Specific gravity of oil = 0.9
Density of oil, ρ = 0.9 × density of water = 0.9 × 1000 = 900 kg/m3
This is solved via way of means of the use of Pascal’s Law, which states that stress at all of the factors in a horizontal route may be same.
Pressure because of oil height = stress due water height
∴ h = 36 m of water column
F= ρ * specific gravity * a * x
F= 900 * 9.8 * (0.6 * 0.6) * 1.2
F= 3810 N
F= 3.81 KN
#SPJ3
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