Question

a rectangular playground has its length more than its breadth by 2m. find the length and breadth of the playground,if area of playground is 440 sq.m.​

Answer 1

Answer:

Length =22, Breadth=20

Step-by-step explanation:

Let length be L so breadth will be L-2

given area=440

=> L*(L-2)=440

=>L²-2L=440

=>L²-2L-440=0

=>L²-22L+20L-440=0

=>L(L-22)+20(L-22)=0

=>(L-22)(L+20)=0

=> L=22 or -20 but length cannot be negative so L=22

So breadth= L-2=22-2=20

Answer 2

Answer:

length = 22m

breadth = 20 m

Step-by-step explanation:

let x be the breadth of rectangular playground( in m).

∴ its length = (x + 2) m

Area = 440 m²

length x breadth = 440

x (x+2) = 440

x² + 2x -440 = 0

x² +22x - 20 x - 440 = 0

x(x +22) -20 ( x + 22) = 0

(x + 22) (x - 20) = 0

∴ x = - 22 or x = 20

since x>0

x = 20 m

∴ length = (x+2) = 20 + 2 = 22 m

breadth = x = 20 m