a rectangular playground has its length more than its breath by 2 m find the length and breadth of the playground if area of playground is 440 sq.m.
Answers
Step-by-step explanation:
Let the length and breadth of the rectangle be
′
a
′
,
′
b
′
.
Given area = 420 sq.m
⇒ab=420 ...(1)
length → increased by 7 meter
breadth → decreased by 5 meter
Area → remains unchanged
⇒(a+7)(b−5)=420 ...(2)
From, (1) , b=
a
420
⇒(a+7)(
a
420
−5)=420
⇒420−5a+
a
2940
−35=420
⇒−a
2
+588−7a=0
⇒a
2
+7a−588=0
⇒a
2
+28a−21a−588=0
⇒a(a+28)−21(a+28)=0
⇒a=21m
ab=420⇒b=20m
∴ Length =21m and breadth =20m
Answer:
Provided area = 420 sq.m.
⇒ab=420 ... (1)
length grew by 7 metres.
decreased by 5 metres in breadth
Area does not change.
⇒(a+7)(b−5)=420 ... (2)
From, this b=
a
420
⇒(a+7)(
a
420
−5)=420
⇒420−5a+
a
2940
−35=420
⇒−a
2
+588−7a=0
⇒a
2
+7a−588=0
⇒a
2
+28a−21a−588=0
⇒a(a+28)−21(a+28)=0
⇒a=21m
ab=420⇒b=20m
∴ 20 metres wide and 21 metres long
Step-by-step explanation:
The formula P=2l+2w, where l seems to be the rectangle's length as well as w is its width, determines the perimeter of a rectangle. The equation A=lw, where l seems to be the length & w is the width, determines the area An of a rectangle.
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