A rectangular plot having dimensions 125m and 75m contains a pain, wnicn is 2.5m wide all around inside. what is the area of path?
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Answered by
0
length and breadth of outher rectangle is 125 c, and 75 cm.
inner rectangle length =125-5(2.5+2.5)
=120
inner rectangle breadth=75-5
=70
area of path=area of outher rectangle-area of inner rectangle
125*75-120*70
=9375-8400
=975cm
answer is 975cm
inner rectangle length =125-5(2.5+2.5)
=120
inner rectangle breadth=75-5
=70
area of path=area of outher rectangle-area of inner rectangle
125*75-120*70
=9375-8400
=975cm
answer is 975cm
MikeTomlinson:
well, the dimensions are in meter
Answered by
1
Dimensions of the outer rectangular plot = 125 m x 75 m
Dimensions of the inner rectangular plot will be ---
Length = 125 - (2.5 + 2.5) = 125 - 5 = 120 m
Breadth = 75 - (2.5 + 2.5) = 75 - 5 = 70 m
Dimensions of the inner rectangular plot = 120 m x 70 m
Area of the path = Area of the outer plot - Area of inner plot
Area of the path = (125 x 75) - (120 x 70)
= 9375 - 8400
= 975 square m
Hence of the path = 975 sq m
Dimensions of the inner rectangular plot will be ---
Length = 125 - (2.5 + 2.5) = 125 - 5 = 120 m
Breadth = 75 - (2.5 + 2.5) = 75 - 5 = 70 m
Dimensions of the inner rectangular plot = 120 m x 70 m
Area of the path = Area of the outer plot - Area of inner plot
Area of the path = (125 x 75) - (120 x 70)
= 9375 - 8400
= 975 square m
Hence of the path = 975 sq m
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