Question

A rectangular plot is 103/4 m long and 47/3 m wide.find the perimeter and area of the plot

Answer 1

Answer:

perimeter will be 2*(103/4+47/3) = 497/6

area will be (103/4× 47/3) = 721/12

Answer 2

✪AnSwEr

${\tt{\red{\underline{\large{Given}}}}}$

• A rectangular plot
• where length = 103/4m and
• Breadth = 47/3 m

${\sf{\green{\underline{\large{To\:find}}}}}$

1. Perimeter
2. and area

${\sf{\pink{\underline{\Large{Explanation}}}}}$

Diagram

$\setlength{\unitlength}{1.05 cm}}\begin{picture}(12,4)\thicklines\put(0,1){ . }</p><p>\put(1,1){\line(1,0){4}}\put(1,5){\line(1,0){4}}\put(1,1){\line(0,1){4}}\put(5,5){\line(0,-1){4}}\end{picture}$

Here

we know that

Area of Rectangle = L × B

=> LB = 103/4 × 47/3 = 4741/12 m²

• The main thing u remember that
• the unit of area is m²
• or unit ²
• Always use this instead at any calculation

Perimeter of Rectangle = 2{L+B}

=>Perimeter= 2{103/4 + 47/3 }

=2{(309 + 188)/12}

= 2(497/12}

=497/6m

• The main thing u remember that
• the unit of Perimeter is m
• or unit
• Always use this instead at any calculation