A rectangular plot is 200sq.mts in area.If its breadth is 10mts, then its perimeters is ?
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Answered by
1
we know
area of rectangle=length×breadth
200=length×10
length=200÷10
length=20mts
now
perimeter of rectangle=2(length+breadth)
=2(20+10)
=2(30)
=60 mtrs
area of rectangle=length×breadth
200=length×10
length=200÷10
length=20mts
now
perimeter of rectangle=2(length+breadth)
=2(20+10)
=2(30)
=60 mtrs
Answered by
4
Given:
The area of the rectangle is 200 square meters.
The rectangle has a breadth of 10 meters.
To find:
The perimeter of the rectangle.
Solution:
A rectangle is a form of a quadrilateral whose opposite sides are equal.
Let us name the rectangle PQRS.
Let us take the length of the rectangle as L meters.
We know that area of the rectangle PQRS is,
Area = Length × Breadth.
200 = L× 10
L = 200/10
L = 20 meters
The perimeter of the rectangle PQRS is,
Perimeter = 2 × (L + B)
Where L and B are the length and breadth of the rectangle, respectively.
Therefore,
Perimeter = 2 × (20 + 10)
= 2 × (30)
Perimeter = 60 meters
Hence, the perimeter of the rectangle PQRS is 60 meters.
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