Question

A rectangular plot is 35 M long and 30 M broad rod of uniform width 2.5 runs along the boundary of the plot inside it find the cost of paving the road with bricks at rupees 10 per square metre

Answer 1

$area \: of \: rectangular \: plot \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = 35 \times 30 = 1050 \\ area \: of \: the \: inner \:part= 30 \times 25 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 750 \\ area \: of \: the \: road = 1050 - 750 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 300 {m}^{2} \: \\ cost \: of \: paving \: on \: the \: road \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 300 \times 10 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3000rs$

Answer 2

Given,

length of rectangular plot,AB=35m Breadth of rectangular plot,BC= 30m

length of road inside park=32.5m

Breadth of road inside park=27.5m

Now, we know=>

Area of road =

Area of rectangle ABCD-

Area of rectangle EFGH.

=> Area of road = (AB×CB) - (EF×GF)

=>Area of road =(35×30) - (32.5×27.5)

=>Area of road = 1050 - 893.75

=>Area of road =156.25m^2.

Hence the area of road to be paved is 156.25m^2.

Now,given=>

Cost of paving 1m^2 road=Rs10

and

Cost of paving 156.25m^2 road

= Rs(156.25×10)

= Rs 1562.5

Hence we get the cost of paving156.25 m^2 road with bricks is Rs 1562.5.

Remember

Area of Rectangle=Length×Breadth

Area of sqaure= (side)×(side)=(side)^2