Question

a rectangular plot is fenced with 150m long wore. find the dimensions of the plot if its length is twice its breadth.

Answer 1

Let breadth of rectangle be x m
      length of  rectangle be  2x m
     Perimeter of rectangle=150m
     perimeter=2(L+B)
      150       =2(2x + x)
       150/2=3x
        75/3=x
         x=25
Breadth=x=25m
Length=2x=2*25=50m 

Answer 2

$\mathfrak{Step-By-Step\:Explanation:}$

Let the breadth of the plot be b meter.

So its length :

$\tt{=twice\;of\:breadth}\\\\\\\tt{=2\times b=2b\:meter.}$

Given :

• Perimeter = 150 m.

$\boxed{\bold{Perimeter=2(length+breadth).}}\\\\\\\textbf{Fom above statement:}\\\\\\\tt{Length=2\:Breadth}\\\\\\\tt{A/Q}\\\\\\\implies\bold{2(2b+b)=150}\\\\\\\implies\bold{2\times 3b=150}\\\\\\\implies\bold{6b=150}\\\\\\\implies\bold{b=\dfrac{150}{6}}\\\\\\\implies\bold{b=25.}\\\\\\\boxed{\boxed{\bold{Length=2\times 25=50\:meter\:\&\:Breadth=25\:meter.}}}$