Math, asked by Anonymous, 1 year ago

A rectangular plot is given for constructing a house having agent of 40 m long and 15 metre in front. According to the law has a minimum of 3 m wide space should be left in front and back each 2 m wide space on each of other sides. Find the largest area where house can be constructed.​

Answers

Answered by xItzKhushix
7

Answer:

\bf{\huge{\underline{\boxed{\tt{\blue{Answer:-}}}}}}

➡️The largest area where house can be constructed is 374 meter square.

Given :-

 A rectangular plot is given for constructing a house ,having measurement of 40m long 15m in the front.

According to the laws a min of 3m wide space is to be left in the front and back 2m wide space on each of the other sides.

To find :-

 The largest area where the house can be constructed ?

\bf{\huge{\underline{\boxed{\tt{\blue{Solution:-}}}}}}

Dimension of the rectangular plot is

Length l=40 m

Breadth b=15 m

According to the law, a minimum of 3m, wide space should be left in the front and back each and 2m wide space on each of other sides.

i.e. leaving the space as per the law the dimension became,

\boxed{L=40-6=34m}

\boxed{B=15-4=11m}

So, The largest area where house can be constructed is given by :-

A= L × B

A = 34 × 11

A = 374 m sq.

Therefore, The largest area where house can be constructed is 374 meter square.

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Answered by Ruchadeshmukh1
0

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