Question

a rectangular plot is given for constructing a house, having a measurement of 40m long and 15m in the front. according to the laws. at minimum of 3m,wide space should be left in the front and back each and 2m wide space on each of other sides. find the largest area where house can be constructed. ​

Answer 1

Let the given rectangular plot be ABCD where AB=15m and BC=40m

According to the given condition, a minimum of 3m wide space should be left in the front and back each and 2m wide space on each of other sides.

Therefore, OD=CL=AP=BK=3m and DN=CM=BJ=AI=2m

So, length of the house of largest area that can be constructed

=EF=AB−(AI+BJ)=15m−(2m+2m)=11m

Similarly, breadth of the house of largest area that can be constructed

=EH=AD−(DO+AP)=40m−(3m+3m)=34m

So, area of house constructed =length×breadth=11m×34m=374m

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Answer 2

Answer:

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