Question

A rectangular plot is given for constructing a house, having a measurement of 40 m long and 15 m in the front. According to the laws, a minimum of 3 m, wide space should be left in the front and back each and 2 m wide space on each of other sides. Find the largest area where a house can be constructed.​

Answer 1

Answer:

Let the given rectangular plot be ABCD where AB=15m and BC=40m

According to the given condition, a minimum of 3m wide space should be left in the front and back each and 2m wide space on each of other sides.

Therefore, OD=CL=AP=BK=3m and DN=CM=BJ=AI=2m

So, length of the house of largest area that can be constructed

=EF=AB−(AI+BJ)=15m−(2m+2m)=11m

Similarly, breadth of the house of largest area that can be constructed

=EH=AD−(DO+AP)=40m−(3m+3m)=34m

So, area of house constructed =length×breadth=11m×34m=374m2

Hope this is helpful for you.