Question

A rectangular plot is given for constructing a house ,having measurement of 40m long 15m in the front.according to the laws a min of 3m wide space is to be left in the front and back 2m wide space on each of the other sides.find the largest area where the house can be constructed.

Answer 1

In given fig.

Length of EF= 40-3-3=34m

Breadth of GF=15-2-2=11m

Now, largest area=34×11=374m².

Answer 2

Answer:

The largest area where house can be constructed is 374 meter square.

Step-by-step explanation:

Given : A rectangular plot is given for constructing a house ,having measurement of 40m long 15m in the front.according to the laws a min of 3m wide space is to be left in the front and back 2m wide space on each of the other sides.

To find : The largest area where the house can be constructed ?

Solution :

Dimension of the rectangular plot is

Length l=40 m

Breadth b=15 m

According to the law, a minimum of 3m, wide space should be left in the front and back each and 2m wide space on each of other sides.

i.e. leaving the space as per the law the dimension became,

$L=40-6=34m$

$B=15-4=11m$

So, The largest area where house can be constructed is given by

$A=L\times B$

$A=34\times 11$

$A=374m^2$

Therefore, The largest area where house can be constructed is 374 meter square.