A rectangular plot measures 300m by 200m. A builder builds three roads 10m wide along the length on either side and one in the middle.He also builds one 10 m wide road in the middle along the breadth .The remaining area is cut into residential plots and sold at the rate of ₹ 500 per m . Calculate the total revenue the builder will generate by selling all the plots
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Answered by
43
Area of three roads along the lenght=3 (L×B)
= 3(300×10)
=3×3000
=9000meter spuare
Area of road along the breadth=L×B
=200×10
=2000m^2
Area of rectangular field=L×B
=300×200
=60000m^2
Area of plot =60000-(9000+2000)
=60000-11000
=49000m
Area of square made by road along the breadth=
side×side
=10×10
=100m^2
Total area of roads=(2000+9000)+100
=11000+100
=11100m^2
Area of total plot=49000-11100
= 37900m^2
Hence, total cost of solding plots for 500 rupees =37900×500
=RS 18950000....
= 3(300×10)
=3×3000
=9000meter spuare
Area of road along the breadth=L×B
=200×10
=2000m^2
Area of rectangular field=L×B
=300×200
=60000m^2
Area of plot =60000-(9000+2000)
=60000-11000
=49000m
Area of square made by road along the breadth=
side×side
=10×10
=100m^2
Total area of roads=(2000+9000)+100
=11000+100
=11100m^2
Area of total plot=49000-11100
= 37900m^2
Hence, total cost of solding plots for 500 rupees =37900×500
=RS 18950000....
atharva4885:
nice
Answered by
1
Answer:
# Area of rectangle plot ABCD:- l×b:- 300m×200m :- 60000m^2
# Area of 3 road along the length:- 3×300m×10m:- 9000m^2
# Area of road along to the breadth :- 200× 10m^2:- 2000m^2
# Area of 3 middle :- 3×10×10m^2
# Area of remaining plots;- 60000m^2 - (9000m^2+2000m^2) - 300m^2
:- 60000m^2+(11000-300)m^2
:-60000-70000m^2.
:-49300m^2
# cost of 1m of plot be 500rupees
# cost of 49300m plot be 500rupees×49300;- 2450000rupees
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