A rectangular plot of a land measures 41 metres in length and 22.5 metres in width. a boundary wall 2 metres high is built all around the plot at a distance of 1.5 m from the plot. find the inner surface area of the boundary wall.
Answers
Answered by
76
The rectangular area about which the wall will be constructed is:
width w = 22.5 + 2 * 1.5 = 25.5 m
length = L = 41 + 2 * 1.5 = 44 m
perimeter = P = 2 (44+25.5) = 139 m
total Length of the wall = P = 139 m
height H = 2 m
Inner surface area = A = H * P = 278 m^2
width w = 22.5 + 2 * 1.5 = 25.5 m
length = L = 41 + 2 * 1.5 = 44 m
perimeter = P = 2 (44+25.5) = 139 m
total Length of the wall = P = 139 m
height H = 2 m
Inner surface area = A = H * P = 278 m^2
Similar questions