A rectangular plot of field measure 12 m by 15 m. A pit 8 m by 6m by 50cm is dug in field and soil removed is spread evenly over the remaining portion of the field . Find the increase in the level of the remaining portion of the field.
Answers
Answer: 18.1818 m
Step-by-step explanation:
area of the field= l/b= 12*15= 180 m^2
volume of the pit= 8*6*50= 2400 m^3
area of the pit= 8*6= 48 m^2
area of the field-area of the pit= 180-48 =132 m^2
rise= 2400/132= 18.1818 m
The increase in the level of soil in the remaining portion of the field will be 0.182 meters.
Step-by-step explanation:
The area of the rectangular plot of field measure 12 m by 15 m is (12 × 15) = 180 square meters.
Now, a pit 8 m by 6 m by 50 cm is dug in field and soil removed is spread evenly over the remaining portion of the field.
Now, the area of the field excluding the pit is [180 - (8 × 6)] = 132 square meters.
Now, the volume of soil removed from the pit is (8 × 6 × 0.5) = 24 cubic meters.
Therefore, if the soil thickness throughout the entire plot excluding the pit is x meters, then we can write
132x = 24
⇒ x = 0.182 meters
Therefore, the increase in the level of soil in the remaining portion of the field will be 0.182 meters. (Answer)