A rectangular plot of land is 103/4 m long and 47/3 m wide. Find the perimeter and area of the plot.
Answers
Legth of the plot, l = 103/4 m
breadth of the plot, b = 47/3 m
Perimeter :
P = 2 × ( l + b )
P = 2 × ( 103/4 + 47/3 )
P = 2 × [ ( 103×3 + 47×4 ) / 4×3 ]
P = 2 × [ ( 309 + 188 ) / 12 ]
P = 2 × [ 497 / 12 ]
P = 994 / 12
P = 497/6 m
Area :
A = l × b
A = 103/4 × 47/3
A = 4841 / 12 m²
LENGTH=103/4
BREADTH=47/3
Step-by-step explanation:
Let's find the perimeter first
THE FORMULA FOR FINDING THE PERIMETER OF A RECTANGLE IS 2(l+b)
So now here is your process with answer for the first part of the sum
2(103/4+47/3)
=2(309+188/12)
=2×497/12
=497/6m(Answer) which in MIXED FRACTION is
82 5/7m
Now we do the second part of the sum
THE FORMULA FOR FINDING THE AREA OF A RECTANGLE IS (l×b)
So now here is your process with answer
103/4×47/3
=4841/12m²(Answer) which I mixed fraction is
400 5/12m²
If you are pleased with my answer please mark me the brainliest.
Bye friend have a good day.