a rectangular plot of land measures 41 m in length and 22.5 m in width. a boundary wall 2 metre high is built all around the plot at a distance of 1.5 metre from the plot. find the inner surface area of the boundary wall
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Given,
length= 41
breadth=22.5
Now, a wall was build 1.5m away from the plot. so the the length and breadth is increased by 1.5ms.
Now, the later
length= 41+1.5= 42.5
breadth=22.5+1.5=24
so, the surface area= l×b
= 42.5 × 24
= 1020 m²
length= 41
breadth=22.5
Now, a wall was build 1.5m away from the plot. so the the length and breadth is increased by 1.5ms.
Now, the later
length= 41+1.5= 42.5
breadth=22.5+1.5=24
so, the surface area= l×b
= 42.5 × 24
= 1020 m²
verma17:
thankyou for doing but answrer is not comming
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