A rectangular plot of land measures 45 m*30 m. A boundary wall of height 2.4 m is built all around the plot at a distance of 1 m from the plot. find the area of the inner surface of the boundary wall.
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Solution:-
L = 45 m
B = 30 m
When a boundary wall is built at a distance of 1 m from the plot all around it.
Length of the inner boundary = 45 + 1 + 1 = 47 m
Breadth of the inner boundary = 30 + 1 + 1 = 32 m
Height of the wall = 2.4 m (Given)
Area of the inner surface of the boundary wall = 2h(L + B)
= 2*2.4(47+32)
= 4.8*79
= 379.2 sq m
Answer.
L = 45 m
B = 30 m
When a boundary wall is built at a distance of 1 m from the plot all around it.
Length of the inner boundary = 45 + 1 + 1 = 47 m
Breadth of the inner boundary = 30 + 1 + 1 = 32 m
Height of the wall = 2.4 m (Given)
Area of the inner surface of the boundary wall = 2h(L + B)
= 2*2.4(47+32)
= 4.8*79
= 379.2 sq m
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