a rectangular puece of oaper 11 ×4 cm is folded without overlapping to make a cylinder of height 4 cm Find the volume of the cylinder
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2
Answer:
Given that,
Length of the rectangiular paper= 11cm
Breadth of the rectangular paper= 4cm
Circumfernce of circular part of cyclinder = 2∏r
also given that cyclinder is rolled along its length
HenceCircumfernce of circular part of cyclinder =Length of the rectangiular paper
2∏r =11cm
2 X 22 / 7 X r = 11
44 / 7 X r = 11
r = 7 / 4 cm
Height of cylinder =Breadth of the rectangular paper = h =4cm
Volume of cyclinder =∏r2h
=22 / 7 x (7/4)2X 4
= 38.5cm3
Answered by
7
Answer:
38.5cm³
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