a rectangular room is 10 metre long, 6 metre wide and 5 metre high. it has two doors 1.5 by 2m each and two Windows 2m by 1.8 m each. find the cost of whitewashing the walls and ceiling of the room at the rate ₹50 per metre square.
Answers
This is the answer with solution. do write the required statementa. thank you
Step-by-step explanation:
length = 10 m
breadth = 6m
height = 5m
Walls + Ceiling = 2(l+b) x h + l x b
= 2(10+6) x 5 + 10 x 6
= 220 m square
area to be white washed = (area of the ceiling + walls) - (area of 2 door + area of 2 windows)
area of ceiling + wall = 220 m square.
Area of 2 door
area = l x b (for 2 doors)
= 2 x 1.5 x 2
= 6 m square
Area of 2 Windows
Area = l x b (for 2 windows)
=l x b x 2
= 1.8 x 2 x 2
= 7.2 m square
area to be white washed = (220m square) - (6 m square + 7.2 m square)
= 220 m square - 13.2 m square
= 206.8 m square
Cost for white washing = Area x Cost per m square
= 206.8 x 50
= Rs. 10340
Therefore cost for white washing = Rs. 10340