Question

a rectangular room is 6 m long 4.8m wide and 3.5m high. find the inner surface area of four walls

Answer 1

heya!

here's ur answer...

given:-

length of the room=6m

breadth of the room=4.8m

height of the room=3.5m

CSA of the inner walls=2h(l+b)

=2×3.5(6+4.8)

=7×10.8

=75.6m²

hope this helps...

Answer 2

Given the length of the room = 6m.

Given the breadth of the room = 4.8m.

Given the height of the room = 3.5m.

Inner surface of four walls = 2(l + b) * h

                                            = 2(6 + 4.8) * 3.5

                                           = 75.6m^2.


Hope this helps!