Question

A rectangular room is 6 meters longer than it is wide, and its perimeter is 32 meters. How do you find the dimension of the room?

Answer 1

Let the width of the room be x m.

Therefore, length= (x+6)m

A/Q 2[x+(x+6)] =32

2 (2x+6)=32

4x+12 =32

4x=32-12

4x= 20

x = 20/4

x= 5

since, width=5m

length= (5+6)m= 11m