A rectangular room is 6m long, 4.8m wide and 3.5m high. find the inner surface area of the four walls.
Answers
Answered by
144
The area of the four walls will be given by:
2( length x height) + 2(width x height)
= 2(6m x 3.5m) + 2( 4.8m x 3.5m)
= 2(21 m²) + 2(16.8m²)
=42m² + 33.6m²
= 75.6m²
The inner surface area of the four walls thus is 75.6m²
2( length x height) + 2(width x height)
= 2(6m x 3.5m) + 2( 4.8m x 3.5m)
= 2(21 m²) + 2(16.8m²)
=42m² + 33.6m²
= 75.6m²
The inner surface area of the four walls thus is 75.6m²
Answered by
29
Answer:
Heya!
here's ur answer...
given:-
length of the room=6m
breadth of the room=4.8m
height of the room=3.5m
CSA of the inner walls=2h(l+b)
=2×3.5(6+4.8)
=7×10.8
=75.6m²
hope this helps...
Similar questions