Question

a rectangular room is 8 m ,6m,3m is to be painted find the cost of painting of the walls if cost of 60 per metre square ?​

Answer 1

Answer:

Step-by-step explanation:

THE LENGHTH = 8M AND BREADTH = 6M AND HEIGHT = 3M

AREA OF FOUR WALLS = 2(L+B) + H

                                        = 2(8+6) +3

                                       = 28 +3

                                        = 31

COST = 60 x 31

           = 1860

Answer 2

cost of painting = 60 × lateral surface area of the room

$l = 8 \\ b = 6 \\ h = 3$

lateral surface area of cuboid =

$2h(l + b)$

so,

$2 \times 3(8 + 6) \\ = 6(14) \\ = 84m ^{2}$

cost of painting,

$60 \times 84 \\ = 5040$

so, the cost of painting is ₹5,040